Algebra Practice Test 2025 – The Complete Guide to Mastering Your Exam Success!

Question: 1 / 400

What is the product of the prime factors of 2310?

2•3•5•7•11

To determine the product of the prime factors of 2310, first, we need to identify its prime factorization. The prime factors of 2310 can be found through a step-by-step division:

1. Start dividing by the smallest prime number, which is 2. Since 2310 is even, it can be divided by 2:

\( 2310 ÷ 2 = 1155 \)

2. Next, we look at 1155. The sum of its digits (1 + 1 + 5 + 5 = 12) is divisible by 3, so we divide by 3:

\( 1155 ÷ 3 = 385 \)

3. Now, 385 is not even, and adding its digits (3 + 8 + 5 = 16) shows it’s not divisible by 3. Next, we try 5 (as it ends in 5):

\( 385 ÷ 5 = 77 \)

4. Finally, for 77, we can see that it divides by 7:

\( 77 ÷ 7 = 11 \)

This gives us the complete factorization:

\( 2310

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3•5•11

2•2•5•7•11

2•3•3•5•7

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