Algebra Practice Test 2025 – The Complete Guide to Mastering Your Exam Success!

Question: 1 / 400

Solve for y in the equation 3y + 12 = 0.

y = 0

y = 4

y = -4

To solve the equation 3y + 12 = 0 for y, you need to isolate y on one side of the equation.

First, start by getting rid of the constant term on the left side. You can do this by subtracting 12 from both sides of the equation:

3y + 12 - 12 = 0 - 12

This simplifies to:

3y = -12

Next, to solve for y, divide both sides of the equation by 3:

3y / 3 = -12 / 3

This simplifies to:

y = -4

Thus, the solution to the equation is y = -4. This confirms that the correct answer is indeed that y equals -4.

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y = 12

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